(3x-5)(x^2-3x+4)=

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Solution for (3x-5)(x^2-3x+4)= equation: 


Simplifying
(3x + -5)(x2 + -3x + 4) = 0

Reorder the terms:
(-5 + 3x)(x2 + -3x + 4) = 0

Reorder the terms:
(-5 + 3x)(4 + -3x + x2) = 0

Multiply (-5 + 3x) * (4 + -3x + x2)
(-5(4 + -3x + x2) + 3x * (4 + -3x + x2)) = 0
((4 * -5 + -3x * -5 + x2 * -5) + 3x * (4 + -3x + x2)) = 0
((-20 + 15x + -5x2) + 3x * (4 + -3x + x2)) = 0
(-20 + 15x + -5x2 + (4 * 3x + -3x * 3x + x2 * 3x)) = 0
(-20 + 15x + -5x2 + (12x + -9x2 + 3x3)) = 0

Reorder the terms:
(-20 + 15x + 12x + -5x2 + -9x2 + 3x3) = 0

Combine like terms: 15x + 12x = 27x
(-20 + 27x + -5x2 + -9x2 + 3x3) = 0

Combine like terms: -5x2 + -9x2 = -14x2
(-20 + 27x + -14x2 + 3x3) = 0

Solving
-20 + 27x + -14x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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